We often must prepare dilute solutions from more concentrated stock solutions. The millimole of stock solutions taken for dilution will be identical to the millimoles in the final diluted solution.
Example 1
You have a stock solution 0.200 M of KMnO4 and a series of 100 mL of volumetric flask. What volumes of the stock solution will you have to pipet into the flask to prepare standard solution of 0.005 M KMnO4?
Solution
Moles of 0.005 M KMnO4
= 0.005 x 100
= 0.5 mmol
We must pipet this amount from the stock solution
0.5 = 0.200 X x
X= 0.5 / 0.200
= 2.5 mL
You have a stock solution 0.200 M of KMnO4 and a series of 100 mL of volumetric flask. What volumes of the stock solution will you have to pipet into the flask to prepare standard solution of 0.005 M KMnO4?
Solution
Moles of 0.005 M KMnO4
= 0.005 x 100
= 0.5 mmol
We must pipet this amount from the stock solution
0.5 = 0.200 X x
X= 0.5 / 0.200
= 2.5 mL
Example 2
How much water should be added in 6.0 M 40 mL of H2SO4 solution to produce a 5.0 M H2SO4 solution ?
Solution
6.0 x 40 mL = 5.0 x Volume
Volume = 48 mL
The amount of water that should be added = 48 – 40 = 8 mL
How much water should be added in 6.0 M 40 mL of H2SO4 solution to produce a 5.0 M H2SO4 solution ?
Solution
6.0 x 40 mL = 5.0 x Volume
Volume = 48 mL
The amount of water that should be added = 48 – 40 = 8 mL
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