Useful unit of concentration in quantitative analysis is normality (N), a one normal solution contain one equivalent per liter.
An equivalent represents the mass of material providing avogadro’s number of reacting units. A reacting unit is a proton (in acid-base reaction) or an electron (in oxidation-reduction reaction). The normality of solution is calculated from:
The advantage of expressing concentration in normality and quantities as equivalent is that one equivalent of substance A will Always react with one equivalent of substance B. For the example one equivalent of KOH(=1 mol) will react with one equivalent of HNO3 (=1mol) or with one equivalent of H2SO4 (1/2 mol)
It useful to recognize that, since :
Once can calculate the volume of two solutions that will react by :
Example 1
Calculate the normality of the solution containing 14.205 g/L of Na2SO4 ( When SO42- reacts with two protons).
Solution
SO42- reacts with 2H+ to form H2SO4
Mol Na2SO4 per L
= 14.205 / 142.05
= 0.1 mol
Number of equivalents Na2SO4
= 0.1 x 2
= 0.2 eq
Normality = 0.2 eq / 1 L = 0.2 N
An equivalent represents the mass of material providing avogadro’s number of reacting units. A reacting unit is a proton (in acid-base reaction) or an electron (in oxidation-reduction reaction). The normality of solution is calculated from:
The advantage of expressing concentration in normality and quantities as equivalent is that one equivalent of substance A will Always react with one equivalent of substance B. For the example one equivalent of KOH(=1 mol) will react with one equivalent of HNO3 (=1mol) or with one equivalent of H2SO4 (1/2 mol)
It useful to recognize that, since :
meq A = meq B
Once can calculate the volume of two solutions that will react by :
Na x mLA = NB x mLB
Example 1
Calculate the normality of the solution containing 14.205 g/L of Na2SO4 ( When SO42- reacts with two protons).
Solution
SO42- reacts with 2H+ to form H2SO4
Mol Na2SO4 per L
= 14.205 / 142.05
= 0.1 mol
Number of equivalents Na2SO4
= 0.1 x 2
= 0.2 eq
Normality = 0.2 eq / 1 L = 0.2 N
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